Re: Axiom of Pairing, Scheme of Replacement from others
- From: "Stephen J. Herschkorn" <sjherschko@xxxxxxxxxxxx>
- Date: Fri, 19 Jan 2007 14:32:54 -0500
MoeBlee wrote:
Stephen J. Herschkorn wrote:
MoeBlee wrote:
Stephen J. Herschkorn wrote:Hmm, looking at Halmos, Kunen, and Suppes, it seems to me that
DoesWhich comprehension schema? I take it you don't mean the separation
(Extensionality, Pairing, Union, Power, Infinity, Comprehension) |-
Replacement?
schema.
"Comprehension," "Separation," and "Specifcation" (not respectively) all refer to the same thing:
For any logical formula f wherein the variable "x" is not free, we
have the universal closure of
There exists x such that for all y, y in x iff (y in z and f).
From looking at http://en.wikipedia.org/wiki/Axiom_of_separation , Isuspect maybe MB thought I was referring to unrestricted comprehension.
Does anyone do that any more?
I just wanted to make sure, especially since as taken in the sense of
the axiom scyhema of separation, your question seems to be whether Z |-
ZF, while it is famous that it is not the case that Z |- ZF. Am I
missing something here?
Actually, I wasn't familiar with the last non-implication. I was trying to remember what I had read sometime before, viz., that the axioms of ZF - Foundation are not independent. I had a vague recollection that Extensionality, Union, Power, Infinity, and Comprehension were sufficient. I guess the correct collection is Extensionality, Union, Power, Infinity, and Replacement, where Infinity implies the existence of the empty set.
Thanks for your input, Moe (and others).
--
Stephen J. Herschkorn sjherschko@xxxxxxxxxxxx
Math Tutor on the Internet and in Central New Jersey and Manhattan
.
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