logarithmic scale starting with 0
- From: "different" <cinquequarti@xxxxxxxxx>
- Date: 20 Jan 2007 03:16:10 -0800
I'm trying to interpolate between to numbers using the logarithm
function.
I divided the inteval between the numbers in 20 parts and use the
equation in:
http://www.mpip-mainz.mpg.de/~deserno/science_notes/log_interpol/log_...
to compute the value at each step.
My problem is that my interval begins with 0.
I've already been suggested to shift the graph by 1. In this way the
equation becomes:
x = (x2 + 1)^f * (x1+1)^(1-f) - 1
But it doesn't work. If I use log10 on the interval [0;100] and f, the
position of the point of which I need the interpolated value, is 1/2 x
should be 10, but the equation gives another number.
Any suggestions?
.
- Follow-Ups:
- Re: logarithmic scale starting with 0
- From: matt271829-news
- Re: logarithmic scale starting with 0
- From: hagman
- Re: logarithmic scale starting with 0
- From: different
- Re: logarithmic scale starting with 0
- Prev by Date: Re: Cantor Confusion
- Next by Date: Re: Surface,which is not second countable
- Previous by thread: Re: Seeking efficient sequential-Carmichael-number generator
- Next by thread: Re: logarithmic scale starting with 0
- Index(es):
Relevant Pages
|