Re: A card game probability



In article <1169756728.912704.141420@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
<"jseppa17@xxxxxxxxx"> wrote:

Take a card deck with 52 cards. Pick cards one by one and compute the
cards by ace, two, three,..., jack, queen, king, ace,..., king, ace,
..., king, ace, ..., king. What is the probability that at least once
you turn a card of the same value as you say aloud? Here ace=1,
jack=11, queen=12, king=13.


A standard computation. If it is a homework problem, consider what was
done in the preceding section of the textbook.
.



Relevant Pages

  • Re: A card game probability
    ... you turn a card of the same value as you say aloud? ... Looking up derangements is a good place to start. ... Rob Johnson ...
    (sci.math)
  • Re: A card game probability
    ... you turn a card of the same value as you say aloud? ... numbers - so your brain wouldn't be a random number generator - hence the ... Rob Johnson ...
    (sci.math)
  • Re: A card game probability
    ... In article, Rob Johnson writes: ... you turn a card of the same value as you say aloud? ... And there's no place like Usenet to observe derangement! ...
    (sci.math)
  • Re: Help on (*Ptr)
    ... Nothing in the contents of the OP's posts to this thread indicate that ... it is an homework problem. ... "This system must keep the numbers of card, name of added users, as ... WYCIWYG - what you C is what you get ...
    (comp.lang.c)
  • Re: A card game probability
    ... you turn a card of the same value as you say aloud? ... numbers - so your brain wouldn't be a random number generator - hence the ... This is then the same as saying what is the probability (nth card = ...
    (sci.math)