Re: Rational Numbers/Irrational Numbers
- From: William Elliot <marsh@xxxxxxxxxxxxxxxxxx>
- Date: Sat, 27 Jan 2007 02:48:30 -0800
On Sat, 27 Jan 2007, David T. Ashley wrote:
"William Elliot" <marsh@xxxxxxxxxxxxxxxxxx> wrote in messageMutually exclusive? You mean disjoint? Don't know what mutually
On Sat, 27 Jan 2007, Logan Lee wrote:
That's correct, but that doesn't mean there are fewer of them.I thought rational numbers are subset of real numbers. ?:It must be that:
Rational numbers are proper subset of real numbers.
Is this right?
All positive reals are a proper subset of all reals, yet there
are just as many positive reals as there are all reals.
Easy example. The set 2N, of positive even integers is a proper
subset of the set N, of positive integers.
The mapping f:N -> 2N, f(n) = 2n is a one to one correspondance
between the two sets. For each n in N, f maps to exactly one
element in 2N and for each element 2k in 2N, there is exactly
one element, viz k in N, such that f maps it to 2k. Thus N and
2N have the same number of elements, ie have the same cardinality.
Assuming that we're still trying to disprove my armchair babblings, note
that your example is also qualitatively different than mine.
Again, the elements of my reasoning were:
a)There are two mutually exclusive (but perhaps not mutually exhaustive)
sets, A and B.
exhaustive means.
b)Every element of A maps to two different elements of B (through twof,g:A -> B
different functions f() and g()).
for all x in A, f(x) /= g(x)
c)The mapping is unique in both directions, and if the domain of f() and g()Which mapping, f,g or both? Unique in both directions? You mean
is A, the ranges of f() and g() are _disjoint_ subsets of B.
injective, 1-to-1?
f(A) /\ g(A) = nulset
Mutually exhaustive means
f(A) \/ g(A) = B ?
Note: (c) may not be immediately obvious, but given a real number such asWhat's A and B in this example?
2/3 + PI, it can only be in the range of f(). 2/3 + PI + PI, on the other
hand, can only be in the range of g(). The range of f() and the range of
g() are disjoint.
The example you gave is qualitatively different.
Ok, the point you're making is?
BTW, you took my reply too personally, I was answering Logan Lee.
.
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