Re: A card game probability
- From: "Hawk" <nospam@xxxxxxxxxx>
- Date: Thu, 25 Jan 2007 16:00:28 -0600
"DOD" <no@xxxxxxxx> wrote in message
news:Xns98C39F3418D8dcodeagmailcom@xxxxxxxxxxxxxxxxx
"Hamk" <nospam@xxxxxxxxxx> wrote in
news:45b91aa8$0$97252$892e7fe2@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx:
<snip>
this would be the same as having two decks of cards, deal one out face
up, and then deal out the next deck face up so they make sets of two,
what are the chances that at least one set of two will be a pair.
Except the Second deck hasn't been shuffled, and is in the order he
describes.
--
DOD
so by compute he means arrange in order, therefore all will be in pairs,
unless the guy forgets where he is in counting.
.
- References:
- A card game probability
- From: jseppa17@xxxxxxxxx
- Re: A card game probability
- From: Hamk
- Re: A card game probability
- From: DOD
- Re: A card game probability
- From: Hamk
- Re: A card game probability
- From: DOD
- A card game probability
- Prev by Date: Re: A card game probability
- Next by Date: Re: Lipschitz continuous function
- Previous by thread: Re: A card game probability
- Next by thread: Re: A card game probability
- Index(es):
Relevant Pages
|