Re: det(A+ tB)

In article <qWbvh.95$gj4.46@xxxxxxxxxxxxxxxxxxxxxxxxxx>,
"Jon Slaughter" <Jon_Slaughter@xxxxxxxxxxx> wrote:


det(A + tB) = det(A B^-1 + t I) * det(B)

(the notation A/B used by one poster should be strongly denigrated),

and why is that? You have such a strong feeling to say such a comment about
it so what is the reason? Is it not to hard to see that A/B = A*B^(-1).
Sure it might be symbolically different about its 1/5 of the number of
symbols to write and just adds confusion when typing in ASCII with no
benefit. So you might not like it but thats tough unless you can give a good
reason against it. A/B is clear and concise while A*B^(-1) is not(and here
I'm specifically talking about when it is written in ASCII).

So please do tell me why the short hand A/B is such a bad thing that it has
to be denigrated.


Let C equal to the inverse of B, supposing it to have an inverse,
then it is quite possible to have A*V <> C*A, since not all matrix
multiplications commute.

And since it is not at all clear whether A/B is to be interpreted as A*C
or as C*A where C = B^(-1), the usage A/B should either clearly be
defined as one or the other of its possible meanings or be avoided.

Note that on the HP48/49/50 calculator, the "division" A/B for matrices
A and B is defined to mean B^(-1)*A.
.

Relevant Pages

  • Re: det(A+ tB)
    ... (the notation A/B used by one poster should be strongly denigrated), ... You have such a strong feeling to say such a comment about ... I'm specifically talking about when it is written in ASCII). ...
    (sci.math)
  • Re: det(A+ tB)
    ... (the notation A/B used by one poster should be strongly denigrated), ... I'm specifically talking about when it is written in ASCII). ... Because matrix multiplication isn't commutative. ...
    (sci.math)
  • Re: det(A+ tB)
    ... Jon Slaughter a écrit: ... (the notation A/B used by one poster should be strongly denigrated), ... You have such a strong feeling to say such a comment about it so what is the reason? ... So you might not like it but thats tough unless you can give a good reason against it. ...
    (sci.math)
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