Re: Elementary group theory: Proof of Fermat-Maas primality-test
- From: mm <mm@xxxxxxxxxx>
- Date: Wed, 31 Jan 2007 16:05:48 +0100
hagman a écrit :
This slightly resembles the procedure to generate good candidates for
factors of an RSA product p*q
as spelled out in my 20 years old Knuth.
To avoid easily factored cases one should be sure that
(1) p-1, q-1 are not divisible by 3
(2) p-1, q-1, p+1, q+1 should have at least one /large/ factor
(3) p/q should not be near a simple fraction.
The goal of the condition (1) is not to avoid easy factoring but to
ensure that 3 is invertible modulo (p-1)*(q-1) and can be used as
encrypting exponent.
mm
.
- References:
- Elementary group theory: Proof of Fermat-Maas primality-test (was: correcting *** ...)
- From: Robert Maas, see http://tinyurl.com/uh3t
- Re: Elementary group theory: Proof of Fermat-Maas primality-test (was: correcting *** ...)
- From: Robert Maas, see http://tinyurl.com/uh3t
- Re: Elementary group theory: Proof of Fermat-Maas primality-test (was: correcting *** ...)
- From: hagman
- Elementary group theory: Proof of Fermat-Maas primality-test (was: correcting *** ...)
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