Re: compact are bounded?
- From: "Antonio" <anton.cali@xxxxxxxx>
- Date: 18 Feb 2007 08:27:14 -0800
On 18 Feb, 16:14, José Carlos Santos <jcsan...@xxxxxxxx> wrote:
On 18-02-2007 14:34, Antonio wrote:
Can you sketch me the following proof, please?
Let E and F be Banach spaces and T : E -> F be a linear map. Suppose T
is compact, i.e., T maps bounded sets into relatively compact sets.
Then T is continuous.
Let B be the closed unit sphere in E. Then T(E) is relatively compact
and therefore is a bounded subset of F.
Is that enough for you?
Best regards,
Jose Carlos Santos
Oh, sure, since compact in a metric space imply bounded.
On the other hand, is it true that a finite rank linear map T : E -> F
(E and F Banach spaces) which is not bounded (i.e., which is not
continuous) is necessarily a compact map?
Thank you, best regards, Antonio.
.
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