Re: what is the maximum number of tetrahedrons a polyhedron may be decomposed into?

On Feb 27, 8:06 pm, "jaialai technology"
<jaialai.technol...@xxxxxxxxx> wrote:
I am pretty sure that this is a fairly basic result but it is not
obvious to me and I am having trouble finding something that explains
this via google.
Well, I think maybe my case is more specific in that all edges of the
tetrahedra have polyhedron vertices as endpoints.
Anyone here know the answer?
Thanks!


I think I have found the answer. The answer is 2n-7 for convex
polygons where n is the number of vertices. Well, I thnk I am right.
Am I?

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