Re: Circle Laying On Curves

"[Mr.] Lynn Kurtz" <kurtz@xxxxxxxxxxxxxxx> wrote in message
news:E97lRXiBaM20Z+twuLy+nDHQ5u+a@xxxxxxxxxx

On Wed, 28 Feb 2007 20:27:17 +0200, "Ioannis" <morpheus@xxxxxxxxxxxx>
wrote:

"Narek Saribekyan" <narek.saribekyan@xxxxxxxxx> wrote in message
news:1172681916.585957.261320@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Consider curves e^(-x) and ln(x) and a tangent unit circle. How can I
fins the center coordinates?

The set of points at distance 1 above the curve exp(-x), is exp(-x) + 1.
Similarly, the set of points at distance 1 below the curve ln(x), is
ln(x) -
1.

Therefore the center of the circle (x,y) will lie at the intersection of
the
curves:
exp(-x) + 1 and ln(x) - 1.


But the curves aren't horizontal at the points of tangency with the
circle. The center of the circle will be one unit away in the normal
direction from the curves, not directly above or below them.

Yes, I already posted a retraction on another article. Need more sleep :-)

--Lynn
--
I.N. Galidakis
http://ioannis.virtualcomposer2000.com/

.

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