Re: Long division

This post not CC'd by email
On 28 Feb 2007 00:36:50 -0800, "user923005" <dcorbit@xxxxxxxxx>
wrote:

Consider (for instance) that all the math we do is essentialy with
polynomials operating against polynomials.

e.g.:
1234 * 5678
That could also be considered as
(1000 * 1 + 100 * 2 + 10 * 3 + 4) * (1000 * 5 + 100 * 6 + 10 * 7 + 8)
Of course, that grouping is arbitrary. We can collect the terms
however we like and still get the same result.

G'day G'day,

Thank you for this insight.

If you give a pointer to the proof in question, I guess that someone
can help you to see it clearly.

Take a look at Dave's reply. This helped me considerably. I wouldn't
be surprised to find there are other approaches.

Best wishes,
--
Quentin Grady ^ ^ /
New Zealand, >#,#< [
/ \ /\
"... and the blind dog was leading."

http://homepages.paradise.net.nz/quentin
.

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