ZFC++



Hi all,

ZFC+Proper classes+Ur elements'ZFC++':is the set of sentences entailed
(from first order logic with identity)by these axioms:

1) Extensionality: AxAy(x=y<->Az(zex<->zey)).

2) ur-element:Ex(Ay(yex<->y=x)).

Definition 1) x is a ur-element<-> Ay(yex<->y=x).

3) Regularity:

Ax((Ez(zex))->Ey(yex & ~Ec(cey & cex & ~c=y))).

4) Schema of Global comprehension: if P is a formula in which x is not
free then all closures of:

ExAy(yex<->(P(y)&Ez(yez)))

are axioms.

Definition 2) x=V <-> Ay(yex<->(y=y & Ez(yez))).

Definition 3) x is a proper class <-> ~Ey(xey).

Accordingly V is a proper class.

Definition 4) x=0 <-> Ay(~yex).



5) Pairing:AaeVAbeVExeVAyeV(yex<->(y=a or y=b)).

6) Union:AaExAy((yex<->Ez(zea&yez))&(Em(aem)<->En(xen))).

7) Infinity:ENeV(0eN&(Ax(xeN->xU{x}eN))).

with 'U' and {x} having the usual definitions.

8) limitation of size:

Ax((Ez(xez)) <-> x is subnumerous to V).

x is subnumerous to V <-> Af((f:x->V) ->(f is injective & ~ f is
surjective)).

9)Power: AaExAyeV((yex<->Az(zey->zea)&(Em(aem)<->En(xen)).

Definition 5) x=K<-> Ay(yex<->y is a ur-element)

so K has all ur-elements as its members.


10)ur-multiplicity:

Ax((Az(zex->zeK)&Eu(xeu))->Ey(y is a ur-element & ~yex)).

Accordingly K is a proper class.

/

Zuhair

.



Relevant Pages

  • Re: ZFC++
    ... by these axioms: ... Schema of Global comprehension: if P is a formula in which x is not ... Accordingly V is a proper class. ... with 'U' and having the usual definitions. ...
    (sci.math)
  • Re: The collection of all sets and proper classes.
    ... by these axioms: ... doesn't occure free, then all closures of: ... Accordingly V is the proper class of all sets. ... with 'U' and having the usual definitions. ...
    (sci.math)
  • Re: ZFC++
    ... by these axioms: ... Accordingly V is the proper class of all sets. ... with 'U' and having the usual definitions. ... You said that this theory is inconsistent, and it is trivial to prove ...
    (sci.math)
  • Re: ZFC++
    ... by these axioms: ... Accordingly V is the proper class of all sets. ... with 'U' and having the usual definitions. ... You said that this theory is inconsistent, and it is trivial to prove ...
    (sci.math)
  • Re: ZFC++
    ... by these axioms: ... Accordingly V is the proper class of all sets. ... with 'U' and having the usual definitions. ... You said that this theory is inconsistent, and it is trivial to prove ...
    (sci.math)