Re: Review of Mueckenheims book.



"Jesse F. Hughes" <jesse@xxxxxxxxxxxxx> writes:

lrudolph@xxxxxxxxx (Lee Rudolph) writes:

"Jesse F. Hughes" <jesse@xxxxxxxxxxxxx> writes:

In category theory, a function is not just a set of ordered pairs. A
function requires that we specify the source and target. So, for
instance, we write id_N:N -> N. The function you're talking about is
formed by taking the inclusion N -> P(N), but this inclusion is a
different function than id.

Of course, in set theory, a function is just a set of ordered pairs
and so there is no need to pick out a domain and codomain. Both id_N
and the inclusion are, in this sense, the same function.

They certainly are not, on any of the several usual accounts of N
(and on the account of "same" which makes it mean "identical";
if "same" means "naturally isomorphic", I guess you're okay).

No, I meant identical.

If a function is defined by its graph (as is often the case for set
theorists),

and which is cool with me

then the identity on N is the set {<n,n> | n in N} and the
natural inclusion N -> P(N) is also the set {<n,n> | n in N} (which
uses the fact that each n is also a subset of N).

Perhaps you thought I was speaking of the map n |-> {n}?

Well, yes. And I also seem to be a bit confused.

When I wrote "the several usual accounts of N", I was thinking of two
in particular. The less popular (but surely not totally unknown?)
has 0 = {} and s(n) = {n} for all n in N. On that account, surely
only 0 is both an element and a subset of N?

The more popular is has 0 = {} and s(n)=n \cup {n}, right?
I have just taken aleph-0 moments to check, and sho'nuff, you're
right there.

Huh.

Lee Rudolph
.



Relevant Pages

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