Re: continuum hypothesis and 0=1



Pierre-Yves.Gaillard@xxxxxxxxxxxxxxx a écrit :
What is "being true"?

Now you are playing dense, are you? Or else, I would suggest you get a good book on logic and styudy it before asking all this string of regressive questions

Anyway : in informal terms, "true" (in arithmetic, aka "number theory") is for things like : "Goldbach hypothesis is true", ie for every natural even number >2, there exsts two primes...". GH could be true, but not provable with the current set of axioms for number theory, i.e. ZFC (where integers stand for finite ordinals). For a similar, but easier to check example, "every Goodstein sequence ends at 1" is a sentence of ZFC, and even of the language of Peano axioms; it is provable in ZFC using transfinite induction up to epsilon_0, and not provable in PA, so we say it is true, but...
.



Relevant Pages

  • Re: Is this set-theoretical argument legitimate?.
    ... contradiction that Fermat's last theorem is ... You are correct that if a counterexample is demonstrable in ZF, ... same counterexample is demonstrable in ZFC. ... The Peano axioms are not a version of the axiom of choice. ...
    (sci.math)
  • Re: Galileos Paradox and the Project of the Reals
    ... Omega is defined in terms of S in a rather incoherent way, ... S does not require ZFC - it's already part of Peano. ... S is part of the Peano axioms already. ... You had the same trouble with the successor function ...
    (sci.math)
  • Re: what makes it true?
    ... (in a very clever way) ... a statement that has no proof from the Peano axioms and yet is true in that model. ... Now it is quite easy to see that any model of ZFC gives rise to a model of Peano arithmetic. ...
    (sci.math)