Re: Simple Problem with Arc Length
- From: "Dirk Van de moortel" <dirkvandemoortel@xxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Thu, 08 Mar 2007 19:50:17 GMT
"Dirk Van de moortel" <dirkvandemoortel@xxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:jxZHh.50995$uU4.233590@xxxxxxxxxxxxxxxxxxxxxxxx
"tonyr1988" <tonyr1988@xxxxxxxxx> wrote in message news:1173379951.787005.316940@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
I'm an undergrad in Calc II, and for some reason I'm having problems
with several arc length problems. I feel that it's a stupid algebra
issue, but it's driving me insane. We're using:
s = integral(sqrt(1 + f'(x)^2), from a to b)
(hope the notation is understandable)
Here's one example of one: the arc length of y = 3/2 * x^2/3 over
[1,8]. Here's where I'm at:
y' = x^-1/3
s = int(sqrt(1 + x^-2/3), from 1 to 8)
Why am I stuck here? I'm having problems with this simple integral.
Could someone help me out a little bit? Our midterm is coming up, and
this is the only big problem that I am having (that I know of :D).
Try substitution
t = sqrt( 1 + x^-(2/3) )
The square root immediately goes away ;-)
Oops... made a little typo.
Can you find it? Exercise :-)
Dirk Vdm
.
- Follow-Ups:
- Re: Simple Problem with Arc Length
- From: tonyr1988
- Re: Simple Problem with Arc Length
- From: tonyr1988
- Re: Simple Problem with Arc Length
- References:
- Simple Problem with Arc Length
- From: tonyr1988
- Re: Simple Problem with Arc Length
- From: Dirk Van de moortel
- Simple Problem with Arc Length
- Prev by Date: Re: Review of Mueckenheims book.
- Next by Date: Re: n Inverse Modulo m
- Previous by thread: Re: Simple Problem with Arc Length
- Next by thread: Re: Simple Problem with Arc Length
- Index(es):
Relevant Pages
|
