Re: Wondering if my idea is right concerning Transfinite Sets
- From: mayost@xxxxxxxxx (Daniel Mayost)
- Date: 8 Mar 2007 18:48:25 -0500
In article <19670998.1173395903081.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxx>,
Peter Whang <peter_junho@xxxxxxxxxxx> wrote:
Take the following series,
1,3,4,8,16,32,64,128,...
Where the first two numbers are 1 and 3 and the rest of them are 2^(n-1).
If we take a set containing exactly all the terms of the series, then cardinality of such set is equal to aleph-null. Since (aleph-null)+1 = (aleph-null) and each number is only finitely greater than 1, the sum of all those terms should equal aleph-null.
On the other hand, we can see that the sum of all first finite number of (n) terms is equal to 2^n (where n>1). If we expand its logic, we see: sum of all members of the series is 2^(aleph-null).
But then it exerts that aleph-null=2^aleph-null.
Is there a fault with the way i treated the transfinite numbers as sums of finite numbers? Please help me out on this one, because I still don't quite get the connection between finite and transfinite numbers
What this example shows is that if X is a set of ordinals, then:
sup {2^x | x in X}
might be different from:
2^(sup X)
--
Daniel Mayost
.
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