Re: How to solve the probability density of z=ax+w?
- From: David Marcus <DavidMarcus@xxxxxxxxxxxxxx>
- Date: Thu, 8 Mar 2007 19:10:00 -0500
matt271829-news@xxxxxxxxxxx wrote:
On Mar 8, 5:41 pm, hhwolf76 <james.zho...@xxxxxxxxx> wrote:
This is a problem
If p(a=0)=1/2,p(a=1)=1/2
a,x,w are mutually independent. x,w are all normal distribution and their 1st and 2nd moment have been known. E(w)=0
Can I get the probability density of z=ax+w?
If a = 0 then the pdf of z is the same as the pdf of w, call it
P_0(z). If a = 1 then z = x + w, so z has a normal distribution whose
mean is the sum of the means of x and w, and whose variance is the sum
of the variances of x and w. Call this pdf P_1(z).
Then, unless I'm overlooking something, the overall pdf of z should be
1/2*(P_0(z) + P_1(z)) (which is, of course, *not* a normal
distribution).
Quite correct.
--
David Marcus
.
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