Re: Review of Mueckenheims book.
- From: mueckenh@xxxxxxxxxxxxxxxxx
- Date: 16 Mar 2007 06:34:50 -0700
On 15 Mrz., 15:24, "William Hughes" <wpihug...@xxxxxxxxxxx> wrote:
On Mar 15, 7:18 am, mueck...@xxxxxxxxxxxxxxxxx wrote:
The question
is "does the EIT contain infinite paths?".
Yes. The "paths" of the EIT are the lines, not the columns.
No.
The elements of the EIT correspond to the nodes of U(T(n)).
No.
A path is composed of nodes, one from each level.
A line of the EIT is composed of bits which are nodes in the picture
of the tree.
A "path" in the EIT consists of one element of the EIT
from each line.
A path of a finite tree does not consist of one element of every level
of the infinite tree.
Since we are not talking about paths in the finite tree
this remark is irrelevant. A "path" in the EIT
consists of one element of the EIT from each line.
That depends how you carry out the projection. Of course you can find
out the Waft Maximum of the set of columns. But that is not very
interesting, because each column has the size aleph_0.
As we are interested in the WM of the set of all finite paths, a good
picture to compare with is the set of all finite lines of the EIT.
Regards, WM
.
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