Re: Cantor Confusion

In article <1174562837.696384.225170@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
mueckenh@xxxxxxxxxxxxxxxxx wrote:

On 21 Mrz., 16:09, "*** T. Winter" <***.Win...@xxxxxx> wrote:
In article <1174481309.873623.92...@xxxxxxxxxxxxxxxxxxxxxxxxxxx>
mueck...@xxxxxxxxxxxxxxxxx
> > What portion of the first node
> > is assigned to your path?
>
> How much does the last term of the geometric series contribute to the
> value o the series? This is the value which the first node contributes
> to he path.

As there is no last term of the geometric series this makes no sense.

Nevertheless, it makes sense to calculate the sum of the series.

Nodes, which no more have reassemblable parts than do eggs, once
cracked, cannot be reassembled.

WM cannot do what all the king's horeses and all the king's men failed
to do, reassemble that which cannot be reassembled.

Nodes, like points, are things which have no parts.

At every node in the tree uncountably many paths go to the left and
uncountably many paths go to the right. I do now know what you are
meaning here.

At no node in the tree there exists a single path. This means: There
are no single paths.

At every node of a CIBT, there are uncountably many paths through that
node.

> In the whole tree there can be no more separated paths than nodes.

Pray give a *proof*, not just a statement.

The number of separated paths up to level n is given by the number of
nodes of level n. No level of the tree has an uncountable number of
nodes.

This is relevant in limiting the number of paths only in finite trees,
as only a last lever imposes any such limits.

Where a last level is missing, so are any limits it can impose.



The number of separated paths up to level n is given by the number of
nodes of level n.

How are "separated paths" different from ordinary paths?

In a CIBT, at each node the directions of branching from that node
separate (partition) the uncountable set of all paths into two
uncountable subsets.


No level of the tree has an uncountable number of
nodes.

Through every node in a CIBT pass uncountably many paths.


Right. There is *no* node where all non-terminating paths are separated
from each other.

There is no point in the tree where more than countably many paths are
separated, although the tree is infinite.

In a CIBT, at every node in the entire CIBT, the directions of branching
from that node separate (partition) the uncountable set of all paths
through that node into two uncountable subsets, one through each of the
two child nodes.



Outside of the tree there is
no mathematics of real numbers.

Whatever is that supposed to mean?

AS far as WM is believes, there seems to be no mathematics anywhere, but
mathematicians know better!
.

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