Re: commutes with translation
- From: A N Niel <anniel@xxxxxxxxxxxxxxxxxxxxx>
- Date: Sat, 31 Mar 2007 05:30:31 -0400
In article <1175319591.265280.238540@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
Fedor <malabar_carotte@xxxxxxxxx> wrote:
hi all,
how can one prove that a linear bounded operator T:L^1(R) -> L^1(R)
that commutes with translation is of the following form:
T(f)=f * \mu
where \mu is a measure (and * is the convolution)?
thanx,
Fedor
Of course, \mu could be a signed measure... or a complex measure?
.
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