Re: commutes with translation

On Mar 31, 11:30 am, A N Niel <ann...@xxxxxxxxxxxxxxxxxxxxx> wrote:
In article <1175319591.265280.238...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,

Fedor <malabar_caro...@xxxxxxxxx> wrote:
hi all,

how can one prove that a linear bounded operator T:L^1(R) -> L^1(R)
that commutes with translation is of the following form:
T(f)=f * \mu
where \mu is a measure (and * is the convolution)?

thanx,
Fedor

Of course, \mu could be a signed measure... or a complex measure?

of course

.