Re: commutes with translation

From: David C. Ullrich <ullrich@xxxxxxxxxxxxxxxx>
Date: Sat, 31 Mar 2007 08:00:37 -0600

On 30 Mar 2007 22:39:51 -0700, "Fedor" <malabar_carotte@xxxxxxxxx>
wrote:

hi all,

how can one prove that a linear bounded operator T:L^1(R) -> L^1(R)
that commutes with translation is of the following form:
T(f)=f * \mu
where \mu is a measure (and * is the convolution)?

As a start, show that T(g*f) = g*T(f) for f, g in L^1.

thanx,
Fedor

************************

David C. Ullrich
.

References:
- commutes with translation
  - From: Fedor

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