linear algebra, inner product spaces
- From: Kiuhnm <"kiuhnm03["@]yahoo.it>
- Date: Mon, 30 Apr 2007 17:33:37 +0200
Let V be a complex inner product space and T a self-adjoint linear operator on V.
I must show that I+iT is non-singular.
I have proven that it is injective, but I have trouble with surjectivity.
My idea was to show that for each v in V there exists w in V s.t.
||w+iTw - v|| = 0, exploiting the identity (Ta|b) = (a|Tb).
Kiuhnm
.
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