Differentiation - Stuck :(
- From: mitch@xxxxxxxxxxxxxxxxxx
- Date: 30 Apr 2007 08:27:28 -0700
Can anyone help me out here please:
The equations ux = v^2 + y and vy = x^2 + 2u^2 define u and v as
functions of the independent variables x and y. Show that:
(du/dx) = (uy-4xv) / (8uv-xy)
and
(dv/dx) = (4u^2-2x^2) / (8uv-xy)
Where the differentials are partial.
Just can't see how to apply the following to help me:
(dz/du) = (dz/dx)(dx/du)+(dz/dy)(dy/du)
(dz/dv) = (dz/dx)(dx/dv)+(dz/dy)(dy/dv)
Again, all differentials are partial.
Thanks for any help,
Mitch.
.
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