Re: Prob Solving - Help reqd

On Apr 30, 3:53 pm, Robert Israel <isr...@xxxxxxxxxxx> wrote:
On Apr 29, 10:14 pm, sathishvijay <sathish.vijayaragha...@xxxxxxxxx>
wrote:

Yes the problem was stated very mch correctly (as per the prep
questions)

if xy = 1, what is the value of

2 (x+y)^2
--------------
2 (x-y)^2

That may be the way it was printed in the prep questions, but the
question that would make sense would have

2^((x+y)^2)/2^((x-y)^2)

It makes you wonder why they make something like this a multiple
choice question. You either get it, or you don't. There is no way to
find the wrong answer to this problem; if you have any clue how to
attack the problem, you'll have to get it right. Having five choices
just gives you a twenty percent chance of getting the right answer by
guessing.

(I don't know how these tests work; are there any penalties for
guessing wrong? )

.

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