Re: Prob Solving - Help reqd
- From: OwlHoot <ravensdean@xxxxxxxxxxxxxx>
- Date: 1 May 2007 07:16:10 -0700
On May 1, 2:23 pm, quasi <q...@xxxxxxxx> wrote:
On 1 May 2007 04:30:27 -0700, "christian.bau"
<christian....@xxxxxxxxxxxxxxxxxx> wrote:
On Apr 30, 3:53 pm, Robert Israel <isr...@xxxxxxxxxxx> wrote:
On Apr 29, 10:14 pm, sathishvijay <sathish.vijayaragha...@xxxxxxxxx>
wrote:
Yes the problem was stated very mch correctly (as per the prep
questions)
if xy = 1, what is the value of
2 (x+y)^2
--------------
2 (x-y)^2
That may be the way it was printed in the prep questions, but the
question that would make sense would have
2^((x+y)^2)/2^((x-y)^2)
It makes you wonder why they make something like this a multiple
choice question. You either get it, or you don't. There is no way to
find the wrong answer to this problem; if you have any clue how to
attack the problem, you'll have to get it right. Having five choices
just gives you a twenty percent chance of getting the right answer by
guessing.
(I don't know how these tests work; are there any penalties for
guessing wrong? )
I'm almost certain that Robert Israel's suggested revision matches the
problem as given on the actual test.
In other words, I'll bet that the question on the test itself was
actually OK.
As far as the test prep book, if that book shows solutions, then I'd
be willing to bet that for this question, the printed solution has the
correct problem.
Moreover, for all you know, even the question itself may have been
correctly printed in the test prep book. After all, many students
misinterpret 2^x as 2*x.
If you had to bet, who would you bet on in this case -- the OP or the
test prep book?
I bet the question actually read "If there are integers x and y with
xy = 1 ..",
in which case Robert Israel's interpretation is undoubtedly correct,
because
then x, y = -1, -1 or 1, 1.
.
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