Missunderstanding on integration
- From: polymedes <google@xxxxxxxxxxxxxxxxxx>
- Date: 8 May 2007 13:47:04 -0700
I'm looking for help on this integral:
e^{-\int_{t_0}^{t}p(s)ds} \int_{t_0}^{t} g(r) dr = \int_{t_0}^{t} e^{-
\int_{t_0}^{t}p(s)ds} g(r) dr
why is this true? What I am missing?
.
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