Re: Racing cars on a track
- From: "KBH" <KBH@xxxxxxxxxxx>
- Date: Sat, 19 May 2007 16:39:28 -0400
Oh, from the graphical approximation to the result:
Okay the tangent on the North direction is 470 while the distance to
the low point from the radius is 469 on the 315 azimuth.
L is distance to add to radius
P is distance to add to tangent
r is the starting radius
R is the required radius
t is the starting tangent distance
T is the required tangent distance
t as (t) is known
r as (r) is known
0.7071 * L = P
L + (r) = R
P + (t) = T
T = R
L + (r) = R
P/.7071 + (r) = R
P + (t) = T
T = R
P/.7071 + (r) = P + (t)
1.414227 P - P = (t) - (r)
0.414227 P = (t) - (r)
(r) = 469
(t) = 470
0.414227 * P = 1
P = 2.41
T = 470 + 2.41
T = 472.41
Now forget the graphical approximation:
t is the tangent distance for the outside curve
r is the radius distance to the midpoint of the inside curve
t = 400
r = 370
1.414214 P - P = (t) - (r)
0.414214 P = 30
P = 72.43
T = 400 + 72.43
T = 472.43
Now some terminology explaination:
The curve has a central angle of 90 degrees.
The tangent is the straight into the curve and also the straight out of
the curve. But the tangent-distance is the distance from the
begin-of-curve to the intersection of the tangents. And the
tangent-distance is also the distance from the intersection of the
tangents to the end-of-curve.
So I suppose this is a "Circular Path Curve...within a given circular curve
width"...
And the calculation should easily develop for central angles other than 90
degrees...
.
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