Re: Simple, but a bit hard, Trigonometry problem.
- From: quasi <quasi@xxxxxxxx>
- Date: Thu, 24 May 2007 08:03:24 -0500
On 24 May 2007 04:52:53 -0700, gtsavdar@xxxxxxxxx wrote:
I've managed to solve it but only after a _massive_ number of
calculations.
Is there any other simpler solution? There must be!
If:
a = Sin(5°)
b = Sin(49°)
c = Sin(87°)
then prove that: Sin(73°) = (a^2 - b^2 + a c) / ( 4 a (a^2 - b^2 +
a c) - (a-b+c) )
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If the symbol of degree inside the Sin() does not appear in some
browsers then the problem is the follow:
If:
a = Sin(5 degrees)
b = Sin(49 degrees)
c = Sin(87 degrees)
then prove that: Sin(73 degrees) = (a^2 - b^2 + a c) / ( 4 a (a^2 -
b^2 + a c) - (a-b+c) )
As a separate challenge, find a polynomial relationship between a,b,c.
quasi
.
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