Re: Simple, but a bit hard, Trigonometry problem.
- From: Phil Carmody <thefatphil_demunged@xxxxxxxxxxx>
- Date: 24 May 2007 18:02:42 +0300
gtsavdar@xxxxxxxxx writes:
/ Phil Carmody :
quasi <quasi@xxxxxxxx> writes:
Conjecture 1:
Let r,s,t be integers such that gcd(rs,t)=1, and let a=sin(r),
b=sin(s), c=sin(t). Then c _cannot_ be expressed as a polynomial in
a,b.
What if t is 0?
Then the gcd(rs,t)=1 would be false, so the statement "Let r,s,t be
integers such that gcd(rs,t)=1" would be false too, so the implication
would be true.
Now it remains to show this for t not 0....
k*180 degrees for integer k then.
And if you want to be pedantic, try t=0 r=s=1.
Phil
--
"Home taping is killing big business profits. We left this side blank
so you can help." -- Dead Kennedys, written upon the B-side of tapes of
/In God We Trust, Inc./.
.
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