Re: Simple, but a bit hard, Trigonometry problem.

On Mon, 28 May 2007 15:46:16 -0500, quasi <quasi@xxxxxxxx> wrote:

On Mon, 28 May 2007 15:30:21 -0500, quasi <quasi@xxxxxxxx> wrote:

On Mon, 28 May 2007 14:42:53 -0500, quasi <quasi@xxxxxxxx> wrote:

On Mon, 28 May 2007 14:27:57 -0500, quasi <quasi@xxxxxxxx> wrote:

Finding angles whose sines have a given relation is more problematic.

As a test question, do there exist 3 acute angles with integer degree
measures n1,n2,n3 such that

sin(n1)=sin(n2)*sin(n3)

Ok, that was too easy.

Let n1=30, n2=n3=45.

I'll try to think of a better one.

Ok, here's a "trig problem" ...

Consider the multiplicative group G generated by

{sin(1),...,sin(44)} union {sin(46),...,sin(89)}

where the angles above are in degrees.

Is G the free abelian group with 89 generators?

I mean't 88 generators.

I meant "meant".

(hopefully, this will stabilize)

quasi
.

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