Re: Proof 0.999... is not equal to one.
- From: karl <oudeis@xxxxxxxxxxx>
- Date: Thu, 31 May 2007 09:06:02 +0200
chajadan@xxxxxxxx schrieb:
What is the distance between 0.99999... and one?
Ciao
Karl
The distance is a non-real number I call a dubious number. It is of
indeterminate scale. It would take an infinity of them to equal one,
as mentioned at the end of my analysis. No real number increment would
be able to keep from surpassing one from zero in a finite number of
increments.
While the distance it not a real number, the system of real numbers
cannot allow 0.999... to be one as shown in my proof. In the Classic
Proof, 10x - x requires an element of subtraction that decimal cannot
hope to express in its own terms.
Bounds on the distance are not expressable in decimal notation.
Decimal notation, as described, is unable to express a large class of
real numbers. We know an infinity of numbers exist just after zero,
but decimal can only ever hope to express some reasonbly small
numbers. In between any smallest number decimal can express and zero
lie an infinity of inexpressable real numbers. These real numbers
would require only a finite mutliple to reach one.
--charlie
O.k., a=0.9999... is a real number. b=1 is a real number.
What value has b-a?
Ciao
Karl
.
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