Re: Stat question

On Mon, 04 Jun 2007 13:51:54 -0700, se16@xxxxxxxxxxxxxx wrote:

On 4 Jun, 20:05, quasi <q...@xxxxxxxx> wrote:
The simplest way to deal with this problem is to recognize the
symmetry.

Exactly one of X,Y,Z has to be in the middle. By symmetry, there's no
bias, so the probability P(X<Y<Z)=1/3.

Apart from your other corrections, you might want to adjust this to
reflect six, rather than three, permutations.

Ah, of course -- how silly of me.

Yes, P(X<Y<Z)=1/6

(All permuted orders are equally likely).

quasi
.

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