Re: A Diophantine Equation

Infinitely many of them. Try:

x = (a+b)^2 - 2 b^2
y = (a+b)^2 - 2 a^2
z = a^2 + b^2

for distinct positive integers a and b.
--
Robert Israel isr...@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada

very impressive answer, plz share the method/idea of getting that
arrangement of a and b.
thank you,
regards,
Divij

.

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