Re: Open balls
- From: quasi <quasi@xxxxxxxx>
- Date: Wed, 20 Jun 2007 19:43:36 -0500
On Thu, 21 Jun 2007 00:38:39 +0200, "marcelo" <@alpha@@lll.it> wrote:
Let (M,d) be a metric space. Denote with B(p,t) the open ball with center p
and radius t.
If B(x,r) <= B(x,s) then it is not necessarily r<=s.
What happens if B(x,r) < B(x,s) (that is, B(x,r) is strictly included in
B(x,s) ) ? Can we say once again that it is not necessarily r<=s ?
Of course not.
If B(x,r) is a proper subset of B(x,s) then it must be true that r<s.
quasi
.
- Prev by Date: Re: Separation,Power and Countability.
- Next by Date: Re: I agree with gödel and matheyasevich : Mathematics is too hard for mathemat
- Previous by thread: Re: Open balls
- Next by thread: Re: Open balls
- Index(es):
