Re: logarithmic equations

On Thu, 28 Jun 2007 00:27:45 -0000, conrad <conrad@xxxxxxxxxx> wrote:

If I have the following:

2^x = 3^(x + 1)

How can this be reduced such that
I can solve for x? If I take the logarithm
of the left hand side to the base 2, that
would give me x, but I would be left
with the logarithm of 3^(x + 1) to
the base 2 on the right hand side, which
doesn't help my case.

Using logs to any base you like,

log(2^x) = log[ 3^(x + 1) ]

x log(2) = (x + 1) log(3)

Solve for x.

.