Re: f(n)=n^2+2n =>x^2-Ay^2=1
- From: Vincenzo Librandi <vincenzo.librandweoz@xxxxxxxx>
- Date: Sat, 30 Jun 2007 12:23:48 EDT
Micheal M wrote:
Assume n = 2N
4N^2 +4N +1 - 4N^2 - 4N = 1
(2N + 1)^2 - N(N +1) * 2^2 = 1
x^2 - Ay^2 = 1
If A = N(N+1), then
{x, y} = {2N + 1, 2} is a root.
Hi, Michael
It's equivalent my formula
(1) to x^2-Ay^2=1 for Sci-math,
(please, see)
If A=N(N-1), then
(x,y) = (2N-1, 2)
Regards,
Vincenzo Librandi
.
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