Re: x^4+y^3=z^2
- From: Gerry Myerson <myerson@xxxxxxxxxxxxxxxxxxx>
- Date: Fri, 13 Jul 2007 13:11:50 EDT
Use standard techniques for solving Pell's equation to get solutions
to x^2 = 3m^2 + 3m + 1. Then let y = m^2 + m and z = m^3 + a^2
and you'll have a solution to x^4 + y^3 = z^2.
.
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