Re: set theory : the blunder
- From: tommy1729 <tommy1729@xxxxxxxxx>
- Date: Sat, 14 Jul 2007 14:07:53 EDT
On Sat, 14 Jul 2007 10:15:42 EDT, tommy1729
<tommy1729@xxxxxxxxx>
wrote:
I no way. I said:
wanna get personal hmm ?
yes way !! and once again you snip to much !!!
this is what you said earlier !! :
Of course note, since you are an idiot.
although (y,z) is y,z [bla blah]
sounds pretty personal to me !
so dont play good cop , bad cop with me.
claim
Look, man, either (y,z) is y or (y,z) is z. Your
(y,z) is y,z
is meaningless
no its not.
(x-3)(x-2)=0
solution (3,2) or 3,2
rather the difference is meaningless so i remove it (the brackets )
(3,2) different from 3,2 is the real meaningless.
(at least in standard math lingo).
aha
Try to FORMALIZE it in a logical system of your
choice:
(x,y) = y,z [???]
no (x,y) = x,y
and if i said otherwise it was a typo.
it follows naturally from (x)=x
Though
[[x,y]] = [x,y]
does make sense (in a certain framework),
and in a similar way (x,y)=x,y !
[x,y] = y,z
doesn't. (See comments above.)
nope it doesnt , if you read that from me it was a typo, not my point of view.
For example, in my theory of heaps
"[y,x]"
is a name/term referring to a heap.
your theory ???
that means you disagree too on cantor :p
i havent seen your theory...
you accused me before of not fully defining my replacement theory , but i havent seen your theory ( which you suddenly dare to introduce) either.
and if your theory has heaps in the way i have bags its stolen , and you actually agree with me , and against cantor.
wheither you want that or not.
While
"x,y"
is just a list of names/terms/variables (each of
which is referring to
a heap); but "x,y" itself does not refer to a certain
heap. Which one?
If you want to refer to the heap which has (at least)
x and y as
constituents use the term
"[x,y]".
you assume x and y to be unique , this is not neccesary.
Here we have:
x c [x,y]
y c [x,y]
and x E of (x,y) and y E of (x,y)
and x E of x,y and y E of x,y
tommy1729
.
x and y are constituents of [x,y].
F.
--
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