Re: set theory : the blunder
- From: tommy1729 <tommy1729@xxxxxxxxx>
- Date: Sat, 14 Jul 2007 18:35:32 EDT
[x,y].
Here we have:
x c [x,y]
y c [x,y]
With other words, x and y are constituents of
Now if we have x = [a, b], then
[x, y] = [[a, b], y] = [a, b, y].
F.
--
E-mail: info<at>simple-line<dot>de
i agree on that...
so we agree
now what ?
its logical x= (x) thats what
tommy1729
.
- Follow-Ups:
- Re: set theory : the blunder
- From: G . Frege
- Re: set theory : the blunder
- References:
- Re: set theory : the blunder
- From: G . Frege
- Re: set theory : the blunder
- Prev by Date: Re: homomorphism from D6 to S5 or A5
- Next by Date: Re: cube root of a given number
- Previous by thread: Re: set theory : the blunder
- Next by thread: Re: set theory : the blunder
- Index(es):