Re: looking for a parameter solution

tommy1729 wrote:

all variables are positive integers

2x^5 - 2 - 3ny³ + 3n = 0

Hi tommy,
you can write your equation better?

......3*n*y^3 or
......(3*n*y)^3

Regards,
Vincenzo Librandi

2*(x^5) -2 -3*n*(y^3) + 3*n = 0

greets
tommy1729
.

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