English question...
- From: "mina_world" <mina_world@xxxxxxxxxxx>
- Date: Mon, 16 Jul 2007 14:37:33 +0900
Hello sir~
Show that a group G with at least two elements but with
no proper nontrivial subgroups must be finite and
of prime order.
---------------------------------------------
I want to know what the word "but with" means ?
is these "but" meaningless ?
For reference, I can show it.
Anyway, group G must be cyclic by assumption.
If |G| is infinite, then G~Z.(iso)
so, G has proper nontrivial subgroups.
so, contradiction.
If |G| is not prime,
then there is "d" such that d | |G| and 1< d < |G|.
Let G = <a>
|a^(n/d)| = n / ((n/d), n) = d.
so, <a^(n/d)> is proper nontrivial subgroup.
so, contradiction.
.
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