Re: Ultimate debunking of Cantor's Theory



In article <1184600016.546797.245400@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
WM <mueckenh@xxxxxxxxxxxxxxxxx> wrote:

On 15 Jul., 23:39, Virgil <vir...@xxxxxxxxxxx> wrote:

- Matheology requires to have diagonals which have infinitely more
digits than the numbers of the due matrix.

Math requires the "diagonal" in a Cantor diagonal proof to have as may
digits as there are strings/numbers listed. I have no idea where WM's
"due matrix" arises in Cantor's or anyone's, diagonal proofs.
It must be a part of his MathUnrealism.

You contradict yourself.

I do not contradict anyone except WM.

You answered my question:
4) Can a diagonal be twice as long as the width of the list is?
by
Yes.

That's a clear statement.

Regards, WM

Infinite "lengths" can be "twice" as long as themselves, since twice one
of them is only an equally infinite amount.
.



Relevant Pages

  • Re: An uncountable countable set
    ... You have not proved - or even given any justification at all - that this ... This is exactly the same with Cantor's diagonal proof which not valid ... justification at all - that this process has any meaningful limit. ... All digits of a number must be indexed by natural numbers. ...
    (sci.math)
  • Re: Cantor and the binary tree
    ... >> The diagonal proof is valid. ... > digits of the antidiagonal and the digits of the lines. ... he is in no position to judge intermingling of limits. ...
    (sci.math)
  • Re: Cantor and the binary tree
    ... >> The diagonal proof is valid. ... and mathematics in the last centuries have been ... But there can be set up a bijection between the ... > digits of the antidiagonal and the digits of the lines. ...
    (sci.math)
  • Re: Ultimate debunking of Cantors Theory
    ... Math requires the "diagonal" in a Cantor diagonal proof to have as may ... digits as there are strings/numbers listed. ...
    (sci.math)
  • Re: Cantor Confusion
    ... >> adding more and more digits to the number that you are constructing. ... That a infinite string of decimal ... And indeed, it can be done in the n-adics, where such ... you can show (with the diagonal proof) that the n-adics are *not* countable ...
    (sci.math)

Quantcast