Re: compute this
- From: tommy1729 <tommy1729@xxxxxxxxx>
- Date: Tue, 17 Jul 2007 07:29:39 EDT
On Mon, 16 Jul 2007 16:08:56 EDT, tommy1729
<tommy1729@xxxxxxxxx>
wrote:
On Sun, 15 Jul 2007 18:08:32 EDT, tommy1729
<tommy1729@xxxxxxxxx>
wrote:
sum from 1 to infinity for both integers a and b
[a^2 + 2*b^2 + ab*root(8)]^-1
??? The sum is obviously infinite.
others dont seem to agree on that ...
So what? The sum is obviously infinite. This
is clear by comparison with the integral of
1/(x^2 + y^2) over the set of (x,y) in the
first quadrant with x^2 + y^2 > 1 (that
integral is obviously infinite. Hint:
polar coordinates.)
(Nobody's said what the sum _is_, by the way.)
tommy1729
tommy1729
************************
David C. Ullrich
************************
David C. Ullrich
im sorry , your right
.
- References:
- Re: compute this
- From: David C . Ullrich
- Re: compute this
- Prev by Date: Re: compute this
- Next by Date: Re: ... and twenty four months.
- Previous by thread: Re: compute this
- Next by thread: Are closed operators maximal?
- Index(es):
Relevant Pages
|