(2^p) - 1 = p_1 (prime numbers)
- From: Vincenzo Librandi <vincenzo.librandweoz@xxxxxxxx>
- Date: Sat, 21 Jul 2007 02:14:56 EDT
Let p, p_1 prime numbers
and h=2^n (with n>=0)
(2^p) - 1 = p_1
if and only if
p = 3 + log_2 (h)
Regards,
Vincenzo Librandi
.
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