Nonaquark Conjectured By Aiya-Oba

"The square of a pair of quarks (meson), equals a proton and a neutron."- Aiya-Oba (Poet/Philosopher).

Thus; (u + d)^2 = (2u + d) + (2d + u)

Where u, (up quark) is 1, and d, (down quark) is (u + 1).

Such that:

{1 + (1 + 1) }^2 = {(2 x 1)+(1+1)} + {2 x (1+1)+1}

= 3^2 = 2 + 2 + 2 x 2 + 1

= 9 = 4 + 5

= 9 = 9

Q E D.

Proton = (uud)and Neutron =(ddu).
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