Re: Solving for X ?? Stumpes


(2^T + 3^T -13) / (2T^(T-1) + 3T^(T-1))

which doesn't seem to be reducible either for me.

It doesn't matter, since it's wrong. The derivative
of 2^T + 3^T is (ln 2)2^T + (ln 3)3^T. In any case,
why does the expression have to reduce to a nice
form to use Newton?

You are right about the derivative of course, thank you.

.