Re: Express each of the other trigonometric functions of t in terms of sec t.
- From: Will H <will.hermann@xxxxxxxxx>
- Date: Wed, 01 Aug 2007 20:52:09 -0700
On Aug 1, 11:36 pm, William Hughes <wpihug...@xxxxxxxxxxx> wrote:
On Aug 1, 11:20 pm, Will H <will.herm...@xxxxxxxxx> wrote:
The math problem:
Express each of the other trigonometric functions of t in terms of sec
t.
Can this be done with csc t and sin t since they do not contain x (ie
cos t = x therefore one can determine cos t in terms of sec t because
sec t = 1/x).
Thanks for all your help.
A bit confusing (you don't need to set cos t = x)
but yes the basic idea is that cos t = 1 / sec t
So if I have sec t I can get cos t.
Now, if I have cos t I can get sin t (how?)
Now I have both sin t and cos t. Are there
any trig functions that I can't get?
- William Hughes
Are you saying that if cos t = 1/ sec t, then sin t would = +- sqrt(1-
(1 / sec t)^2)
with all that being said then I guess you could figure out the other
three functions?
.
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