Re: How to prove that the space of signed measures is complete?



On 11 Aug, 09:20, victor_meldrew_...@xxxxxxxxxxx wrote:

As the sequene (m_n) is Cauchy, it has a subsequence
(m'_n) with ||m'_n-m'_{n+1}|| < 1/2^n.
We may as well replace (m_n) by (m_{n+1}).
Now set s_n = m_{n+1} - m_n. Now we are effectively
looking at the sum m_1 + s_1 + s_2 + ... of measures.

Now the question is can we reverse order of summation in
the double sum of s_k(A_i)?
But sum_i |s_k(A_i)| <= ||s_k|| <+ 1/2^k so
that sum_k sum_i |s_k(A_i)| is finite.
This allows us to swap the order of summation.

That looks sound. Thanks.

.



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