Re: approximation by series expansion



rembremading <rembremading@xxxxxxx> writes:

@Robert Israel

Sorry, for my delayed response. Time shift between Germany and Vancouver
seems to be considerable.
And sorry for my inexactness. But your interpretation was right.
I wanted to approximate
1/(a-x) = 1/(a-cos(theta)) in the region x=[0..1], where a>1 is a
parameter.
And I wanted a reasonable good approximation for arbitrary a in the entire
interval of x.
The taylor expansion usually fails on one end of the intervall and when you

fix it to both ends it fails in the middle ...
Chebyshev approximation is realy quite good. (I remeber, that I did
consider
it before)
However I will face the problem that I have to evaluate the integral for
the
coefficient.
I will have to do this in each step of my numerical simulation, since a
changes everytime.
But maybe I can use this Clenshaw-Curtis quadrature formulae for the
coefficients (http://en.wikipedia.org/wiki/Clenshaw-Curtis_quadrature).
Then I can even get a simple algebraic expression in terms of parameter a.
Up to now I don't understand how I can calculate the "Nyquist frequency"
for
my problem, that is what N will be in this formula on wikipedia.

I have a formula for the coefficients (obtained with the help of Maple):

c_j = 1/pi int_{-pi}^pi 2/(2 a - 1 - cos(t)) cos(j t) dt
= 2/(-1+a)^(1/2)/a^(1/2)*((2*a-1)*((-1+a)*a)^(1/2)+2*a^2-2*a)^j*
((-8*a+1+8*a^2)*((-1+a)*a)^(1/2)+8*a^3+4*a-12*a^2)^(-j)
--
Robert Israel israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.



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